(2s-1)^2=225 and give the checking
1. (2s-1)^2=225 and give the checking
[tex] \sqrt{(2s-1)^{2}} = \frac{+}{} \sqrt{225} \\ \\ 2s - 1=\frac{+}{} 15\\ \\ 2s-1 =+15\\ 2s/2 = (15+1)/2\\ s=8\\ \\ 2s-1=-15\\ 2s/2=(-15+1)/2\\ s=-7 [/tex]
ANSWER:
s = + 8 and x = -7
Check:
[tex] x=8\\(2(8)-1)^{2}=225\\ (16-1)^{2}=225\\ (15)^{2}=225\\ 225=225\\ \\ x=-7\\(2(-7)-1)^{2}=225\\ (-14-1)^{2}=225\\ (-15)^{2}=225\\ 225=225 [/tex]
2. (2s-1) 2=225 quadratic equation
(2s-1)^2=255
squareroot(2s-1)^2=squareroot
255
2s-1=15
2s-1/=/15
s-1=+/- 7.5
s=+7.5-1
s=6.5
s=(-7.5)-1
s=-8.5
3. square root of (2s-1)^2=225
the answer is 2s-1=15
then equate it by zero the final answer is
2s-16
4. (2s-1)2+225 please solve the quadratic equation by extracting square roots
s=+_ square root of -223 over 2
5. (2s-1)^2=225 extract to square roots
Answer:
2s-1 = √225
2s= 1±15
s = (1±15)/2
solution 1
s = (1+15)/2
= 8
solution 2
s = 1-15/2
= -7
6. How to find the squaroots of (2s-1)squared=225?
√(2s-1)² = √(225)
2s - 1 = +15, -15
2s = 1 + 15
2s/2 = 16/2
s = 8
2s = 1 - 15
2s/2 = -14/2
s = -7
ANSWER: The roots are 8 and -7.
Check:
x = 8
(2(8) - 1)² = 225(16-1)² = 225
(15)² = 225
225 = 225
x = -7
(2(-7)-1)² = 225
(-14-1)² = 225
(-15)² = 225
225 = 225
7. Solve by extracting square root: (2s –1)^2 = 225
Answer:
s1 = 8
s2 = -7
Step-by-step explanation:
[tex] \sqrt{(2 {s - 1)}^{2} } = + - \sqrt{225} [/tex]
[tex]2s - 1 = + - 15[/tex]
[tex]s = \frac{1 + - 15}{2} [/tex]
[tex]s1 = \frac{1 + 15}{2} = \frac{16}{2} = 8 [/tex]
[tex]s2 = \frac{1 - 15}{2} = \frac{ - 14}{2} = - 7[/tex]
#AnswerForTrees
8. Solve The ff.quadratic equations by extracting square roots. (2s-1)^2=225
(2s-1)^2=225
2s-1+1=225+1
2s=226
s=113
9. 4ײ-225=0 3h²-147=0 (×-4)²=169 (K+7)²=289 (2s-1)²=225
6. x=15/2, -15/2
7. h=7, -7
8.x=19,-7
9.k=10,-24
10.No Solution
10. how to solve (2s - 1)14 = 225
Answer:
s=239/28
Step-by-step explanation:
(2s-1)×14=225
remove the parentheses
28s-14=225
move the constant to the right
28s=225+14
calculate
28s=239
divide both sides
solution:
s=239/28
11. with solution (2s–1)^2–225=0
(2s−1)2−225=0
Step 1: Simplify both sides of the equation.
4s^2−4s−224=0
Step 2: Factor left side of equation.
4(s+7)(s−8)=0
Step 3: Set factors equal to 0.
s+7=0 or s−8=0
s=−7 or s=8
Answer:
s=−7 or s=8
12. Please answer this (2s-1)²=225
Answer:
s=8 or s=-7Step-by-step explanation:
(2s-1)²=225
2s-1=±√225
2s-1=±15
2s-1=+15
2s=16
s=82s-1=-15
2s=-14
s=-7#JuneChallenge
13. equation the value of the variable 1. x²=812. a²-36=03. 2s²=504.(2s-1)²=2255. 4x²-225=0
Answer:
2=4/5-1 3=5/0-23=3/1-3 hope ots helps
14. 10. (2s - 1)2 = 225what the answer
Answer:
s = 8
Step-by-step explanation:
is the "2" in (2s-1) an exponent???
if it is an exponent, then the answer should be:
(2s-1)²=225
2s²-2s+1-225=0
s= 8
15. (2s-1)²-225=0 with solution please
Answer:
(2s-1)(2s-1)-225=0
4s²-2s+1-225=0
4s²-2s-224=0
Step-by-step explanation:
ganyan?
16. solve using extracting square roots (2s - 1)2 =225
Answer:
( 2s - 1 )² = 225
A.
(2s-1)² = 225
• √(2s-1)² = √225
• 2s-1 = 15
• 2s = 15 + 1
• 2s = 16
• 2s/2 = 16/2
• s = 8
B.
(2s-1)² = 225
• √(2s-1)² = √225
• 2s-1 = -15
• 2s = -15 + 1
• 2s = -14
• 2s/2 = -14/2
• s = -7
Therefore, x = 8 and x = -7
Step-by-step explanation:
17. (2s-1)²=225 QUADRATIC EQUATION EXTRATING BY SQUARE ROOTS.
The answer to that is S = 8
18. what is the squar root of (2s -1)² 225 = 0
Answer:
s = 8 and s = -7
Step-by-step explanation:
√(2s - 1)² = √225
2s - 1 = 15 2s - 1 = -15
2s = 15+1 2s = -15+1
s = 16/2 s = -14/2
s = 8 s = -7
19. How to solve this (2s-1)^2=225this is my homework,,please answer this,,,,,,thank you;)
(2s-1)^2=225
2s-1=+or-√225
2s-1=+or-15
2s=1+or-15
first solution is
2s=1+15
2s=16
s=8
second solution is
2s=1-15
2s=14
s=7
20. what is the answer here (2s-1)2=225
(2s−1)(2)=225
Step 1: Simplify both sides of the equation.
(2s−1)(2)=225
(2s)(2)+(−1)(2)=225(Distribute)
4s+−2=225
4s−2=225
Step 2: Add 2 to both sides.
4s−2+2=225+2
4s=227
Step 3: Divide both sides by 4.
4s/4=227/4
s=227/4
21. ( k + 4 )² = 289 CHECKING ? ( 2s - 1 )² = 225 CHECKING ?
(k + 4)² = 289
Take the square root of both side
√(k + 4)² = √289
k + 4 = 17 and k + 4 = -17
k = 17 - 4 and k = -17 - 4
k = 13 and k = -21
If k = 13
(13 + 4)² = 289
17² = 289
289 = 289
Ik k = -21
(-21 + 4)² = 289
(-17)² = 289
289 = 289
(2s - 1)² = 225
Take the square root of both side
√(2s - 1)² = √225
2s - 1 = 15 and 2s - 1 = -15
2s = 16 and 2s = -14
s = 8 and s = -7
If s = 8
(2(8) - 1)² = 225
(16 - 1)² = 225
15² = 225
225 = 225
If s = -7
(2(-7) - 1)² = 225
(-14 - 1)² = 225
(-15)² = 225
225 = 225
22. Extracting square root of (2s-1)^2= 225
SOLVE THE QUADRATIC EQUATION (SQUARE ROOT METHOD)
The solutions that satisfy the quadratic equation (2s-1)²= 225 with the square root method are s = 8 and s = -7.
Definition of Quadratic Equation
A quadratic equation is an equation with a variable to the second power as its highest power term.
The Standard Form of a Quadratic Equation:
ax² + bx + c = 0
where:
x represents an unknown (variable)a, b, and c represent known numbers, where a ≠ 0How could you solve such a quadratic equation?
There are three basic ways to solve the quadratic equations:
to factor the quadratic equationto taking the square rootsto use the quadratic formulaUsually, you will not be told which method to use. You will have to make that decision yourself.
However, here are some guidelines as to which methods are better in different situations.
Try Factoring first. If the quadratic factors easily, this method is very quick.Look at the side of the equation containing the variable. Is that side a perfect square? If it is, then you can solve the equation by taking the square root of both sides of the equation. Don't forget to include a ± sign in your equation once you have taken the square root.Finally, use the Quadratic Formula. Any quadratic equation can be solved by using the Quadratic Formula.From the given question, it is asked to use the square root method.The equation
(2s-1)² = 225Take the square root of both sides of the equation
√(2s-1)² = √225Then, 2s-1 = ±15
2s-1 = 15 ⇒ 2s = 15 + 1 ⇒ s = 16/2 ⇒ s = 82s-1 = -15 ⇒ 2s = -15 + 1 ⇒ s = -14/2 ⇒ s = -7Therefore, the following values of s satisfy the equations s = 8 and s = -7.
Learn more about the quadratic equations here:
https://brainly.ph/question/312177
#SPJ5
23. how to get S=8 by (2s-1)2 =225?
( 2s -1)² = 225
√(2s-1)² = + or - √225 / take the sqrt of both sides
2s -1 = 15
2s = 16
s = 8
24. what is the square root (2s-1)²-225=0
Answer:
-7and8 are the square root
25. How to solve this (2s-1)^2 =225 by using isolating the roots.
Answer:
s1=8, s2=-7
Step-by-step explanation:
(2s-1)²=225
√(2s-1)²=√225
2s-1=±15
Equate:
2s-1=15
2s=15+1
2s=16
2s/2=16/2
s1=8
2s-1=-15
2s=-15+1
2s=-14
2s/2=-14/2
s2=-7
26. value of variable of (2s-1)²=225
Answer:
s = 8
(2(8)-1)^2=225
(16-1)^2=225
(15)^2=225
27. solve the following quadratic equations by extracting square roots (2s-1)^2=225
(2s-1)²=225
√(2s-1)²=√225
2s-1= 15 ; 2s-1= -15
2s= 15+1 ; 2s= -15+1
2s=16 ; 2s= -14
2s/2=16/2 ; 2s/2= -14/2
s=8 ; s= -7
28. (2s-1)^2 - 225=0 what is the answer and please check
This is the answer if you just need to find the answer in this format: a+b+c=0. If the format needed is a+b+0=c, you just need to transpose the -224 to the other side and it will turned out to be in positive form (224).
29. How to solving (2s-1) = 225
(2s−1)=225
2s=225+1
2s=225+1
2s=226
2s/2=226/2
s=113
30. ( k + 4 )² = 289 SOLUTION ?? ( 2s - 1 )² = 225 SOLUTION ??
( k + 4 )² = 289
√( k + 4 )² = √289
k + 4 = 17
k = 17 - 4
k =13
( 2s - 1 )² = 225
√( 2s - 1 )² = √225
2s - 1 = 15
2s = 15 + 1
2s = 16
s = 8( k + 4 )² = 289
Square root them because there's an exponent in the left side given.
√ ( k + 4 )² = √ 289
k + 4 = 17
k = 17 - 4
ANSWER ==> k =13
( 2s - 1 )² = 225
The same to it, square root them.
√ ( 2s - 1 )² = √ 225
2s - 1 = 15
2s = 15 + 1
2s = 16
2s/2 = 16/2
ANSWER ==> s = 8
